Q:

Factorization : 3a2-10a+8

Accepted Solution

A:
Answer:  (a - 2) • (3a - 4)Step-by-step explanation:  (3a2 -  10a) +  8Trying to factor by splitting the middle term 2.1     Factoring  3a2-10a+8 The first term is,  3a2  its coefficient is  3 .The middle term is,  -10a  its coefficient is  -10 .The last term, "the constant", is  +8 Multiply the coefficient of the first term by the constant   3 • 8 = 24 Find two factors of  24  whose sum equals the coefficient of the middle term, which is   -10 .       -24     +     -1     =     -25         -12     +     -2     =     -14         -8     +     -3     =     -11         -6     +     -4     =     -10     That's itRewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -6  and  -4                     3a2 - 6a - 4a - 8 Add up the first 2 terms, pulling out like factors :                    3a • (a-2)              Add up the last 2 terms, pulling out common factors :                    4 • (a-2)Add up the four terms of step 4 :                    (3a-4)  •  (a-2)Which is the desired factorizationFinal result :  (a - 2) • (3a - 4)