The function f(x) = 20(3)^x represents the growth of a fish population every year in a local lake. Jesse wants to manipulate the formula to an equivalent form that calculates every half-year, not every year. Which function is correct for Jesse's purposes?
Accepted Solution
A:
We need the exponents law
[tex]a^{bx}=(a^b)^x[/tex] So if a=3 b=1/2
then [tex]3^{1/2*x}=(3^{1/2})^x[/tex] where x represent every half a year.