the point slope form of the equation of the line that passes through (-5,-1) and (10,-7) is y+7=-2/5(x-10) what is the standard from of the equation

Answer:the standard form of the equation is: [tex]2x+5y=-15[/tex]Step-by-step explanation:we know that the standard equation of a line is given by [tex]ax+by=c[/tex]so, on converting the above point slope form of the equation of the line that passes through (-5,-1) and (10,-7) i.e. [tex]y+7=\frac{-2}{5} (x-10)[/tex] into the standard form of the equation.firstly we'll multiply both side of the equation by 5 to have[tex]5(y+7)=-2(x-10)[/tex][tex]5y+35=-2x+20\\2x+5y=20-35\\2x+5y=-15[/tex]Hence, the standard form of the given equation of line is:  [tex]2x+5y=-15[/tex].